filenames - Return the list of current filenames
filenames ();
Return a string with all the filenames currently being process.
The first filename is the request. If the initial filename use a generate, than this will be the next filename, etc.
Note: In the followings examples, the _ between the { should be removed to make it work.
{_{ filenames(); }}
Written by Pierre Laplante, <laplante@sednove.com>
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1.0 2014-09-09 21:24:14 laplante@sednove.com